(Note: In many versions of Challenge 5, the table is ch5 and column is hash or key .)
But OR is filtered – but maybe only in username field. Test: If filter is global, fails.
String query = "SELECT * FROM users WHERE username = ? AND password = ?"; PreparedStatement pstmt = connection.prepareStatement(query); pstmt.setString(1, username); pstmt.setString(2, password); ResultSet rs = pstmt.executeQuery();
5' AND '1'='2
After bypassing login, you are logged in as admin but see no flag. The flag is stored in another table (e.g., flags ). To retrieve it, you must inject a SELECT without using the word SELECT .
The paper you're referring to is likely a for SQL Injection Challenge 5 from the OWASP Security Shepherd project.
Actually, after testing, the known solution: Sql Injection Challenge 5 Security Shepherd
OR 1=1 = Forces the query to return true for every row in the database. ; = Terminates the original statement.
SELECT * FROM users WHERE user_id = ' [user input] '
We want to find the table names. We suspect the data is in the second column. (Note: In many versions of Challenge 5, the
You can now submit this key to the Shepherd to complete the challenge.
There are two subtypes: